8 Way DMux

In the last exercise, we implemented a 4 way DMux.

In this exercise, we will implement an 8 way DMux. For an 8 way DMux, we need 3 selector pins.

Here we can use one regular (2 way) DMux, and two 4 way DMux's we created in the previous exercise.

Till now, when cascading, I have started from selector[0] and then moved towards selector[n]. In this example I am going the opposite way. We will start with selector[2] and then move on to selector[1] and selector[0].

If you look at the truth table, selector 0 can be used to create 2 sets. The first set, when selector[0] is 0, can result in the output being routed to 'a', 'b', 'c', or 'd'. The second set, when selector[2] is 1, can result in the output being routed to 'e', 'f', 'g', or 'h'.

Here, since we are fanning out into 2 sets, we need to use a regular (2 way) DMux. This DMux will have 2 output lines. Each of these output lines will be fed into a 4 way DMux to create a total of 8 output lines.

The code for the exercise is embedded below.